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"If `logx+logy=log(x+y)`, thena. `x=y`b. `x y=1`c. `y=(x-1)/x`d. `y=x ...
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If log[(x+y)/3] = 1/2 (logx+logy),find the value of x/y+y/x - Class 10
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Proof in logarithm - Prove that log(X/Y) = logX - logY
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Solving log(x + y) = log(x) - log(y)
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Proof of log(x) + log(y) = log(xy)
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First Law of Logarithm | logxy=logx+logy
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Solving the Logarithmic Equation (logx)^2 - 6*logx = 7
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